Minimum Number of K Consecutive Bit Flips

24th June 2024: Today's LC995 Minimum Number of K Consecutive Bit Flips

995 Minimum Number of K Consecutive Bit Flips Hard S Topics Companies You are given a binary array nums and an integer k A k-bit flip is

minimum withdrawal in stake Go to i = 3 , nums is 1 s % 2 == 1 , therefore the bit is effectively 0 We flip starting at i and ending at i + k

minimum number of k consecutive bit flips Tag:隨意刷-已寫過 Source: 995 Minimum Number of K Consecutive Bit Flips 1 題意: In: nums,k Out: 最小Flip次數 由0與1所組成的nums; k為連續幾bit做一次